Is it possible to toggle the visibility of an element, using the functions .hide()
, .show()
or .toggle()
?
How would you test if an element is visible
or hidden
?
Is it possible to toggle the visibility of an element, using the functions .hide()
, .show()
or .toggle()
?
How would you test if an element is visible
or hidden
?
Since the question refers to a single element, this code might be more suitable:
// Checks CSS content for display:[none|block], ignores visibility:[true|false]
$(element).is(":visible");
// The same works with hidden
$(element).is(":hidden");
It is the same as twernt's suggestion, but applied to a single element; and it matches the algorithm recommended in the jQuery FAQ.
We use jQuery's is() to check the selected element with another element, selector or any jQuery object. This method traverses along the DOM elements to find a match, which satisfies the passed parameter. It will return true if there is a match, otherwise return false.
You can use the hidden
selector:
// Matches all elements that are hidden
$('element:hidden')
And the visible
selector:
// Matches all elements that are visible
$('element:visible')
if ( $(element).css('display') == 'none' || $(element).css("visibility") == "hidden"){
// 'element' is hidden
}
The above method does not consider the visibility of the parent. To consider the parent as well, you should use .is(":hidden")
or .is(":visible")
.
For example,
<div id="div1" style="display:none">
<div id="div2" style="display:block">Div2</div>
</div>
The above method will consider
div2
visible while:visible
not. But the above might be useful in many cases, especially when you need to find if there is any error divs visible in the hidden parent because in such conditions:visible
will not work.
None of these answers address what I understand to be the question, which is what I was searching for, "How do I handle items that have visibility: hidden
?". Neither :visible
nor :hidden
will handle this, as they are both looking for display per the documentation. As far as I could determine, there is no selector to handle CSS visibility. Here is how I resolved it (standard jQuery selectors, there may be a more condensed syntax):
$(".item").each(function() {
if ($(this).css("visibility") == "hidden") {
// handle non visible state
} else {
// handle visible state
}
});
From How do I determine the state of a toggled element?
You can determine whether an element is collapsed or not by using the :visible
and :hidden
selectors.
var isVisible = $('#myDiv').is(':visible');
var isHidden = $('#myDiv').is(':hidden');
If you're simply acting on an element based on its visibility, you can just include :visible
or :hidden
in the selector expression. For example:
$('#myDiv:visible').animate({left: '+=200px'}, 'slow');
Often when checking if something is visible or not, you are going to go right ahead immediately and do something else with it. jQuery chaining makes this easy.
So if you have a selector and you want to perform some action on it only if is visible or hidden, you can use filter(":visible")
or filter(":hidden")
followed by chaining it with the action you want to take.
So instead of an if
statement, like this:
if ($('#btnUpdate').is(":visible"))
{
$('#btnUpdate').animate({ width: "toggle" }); // Hide button
}
Or more efficient, but even uglier:
var button = $('#btnUpdate');
if (button.is(":visible"))
{
button.animate({ width: "toggle" }); // Hide button
}
You can do it all in one line:
$('#btnUpdate').filter(":visible").animate({ width: "toggle" });
The :visible
selector according to the jQuery documentation:
- They have a CSS
display
value ofnone
.- They are form elements with
type="hidden"
.- Their width and height are explicitly set to 0.
- An ancestor element is hidden, so the element is not shown on the page.
Elements with
visibility: hidden
oropacity: 0
are considered to be visible, since they still consume space in the layout.
This is useful in some cases and useless in others, because if you want to check if the element is visible (display != none
), ignoring the parents visibility, you will find that doing .css("display") == 'none'
is not only faster, but will also return the visibility check correctly.
If you want to check visibility instead of display, you should use: .css("visibility") == "hidden"
.
Also take into consideration the additional jQuery notes:
Because
:visible
is a jQuery extension and not part of the CSS specification, queries using:visible
cannot take advantage of the performance boost provided by the native DOMquerySelectorAll()
method. To achieve the best performance when using:visible
to select elements, first select the elements using a pure CSS selector, then use.filter(":visible")
.
Also, if you are concerned about performance, you should check Now you see me… show/hide performance (2010-05-04). And use other methods to show and hide elements.
How element visibility and jQuery works;
An element could be hidden with display:none
, visibility:hidden
or opacity:0
. The difference between those methods:
display:none
hides the element, and it does not take up any space;visibility:hidden
hides the element, but it still takes up space in the layout;opacity:0
hides the element as "visibility:hidden", and it still takes up space in the layout; the only difference is that opacity lets one to make an element partly transparent;
if ($('.target').is(':hidden')) {
$('.target').show();
} else {
$('.target').hide();
}
if ($('.target').is(':visible')) {
$('.target').hide();
} else {
$('.target').show();
}
if ($('.target-visibility').css('visibility') == 'hidden') {
$('.target-visibility').css({
visibility: "visible",
display: ""
});
} else {
$('.target-visibility').css({
visibility: "hidden",
display: ""
});
}
if ($('.target-visibility').css('opacity') == "0") {
$('.target-visibility').css({
opacity: "1",
display: ""
});
} else {
$('.target-visibility').css({
opacity: "0",
display: ""
});
}
Useful jQuery toggle methods:
$('.click').click(function() {
$('.target').toggle();
});
$('.click').click(function() {
$('.target').slideToggle();
});
$('.click').click(function() {
$('.target').fadeToggle();
});
You can also do this using plain JavaScript:
function isRendered(domObj) {
if ((domObj.nodeType != 1) || (domObj == document.body)) {
return true;
}
if (domObj.currentStyle && domObj.currentStyle["display"] != "none" && domObj.currentStyle["visibility"] != "hidden") {
return isRendered(domObj.parentNode);
} else if (window.getComputedStyle) {
var cs = document.defaultView.getComputedStyle(domObj, null);
if (cs.getPropertyValue("display") != "none" && cs.getPropertyValue("visibility") != "hidden") {
return isRendered(domObj.parentNode);
}
}
return false;
}
Notes:
Works everywhere
Works for nested elements
Works for CSS and inline styles
Doesn't require a framework
I would use CSS class .hide { display: none!important; }
.
For hiding/showing, I call .addClass("hide")/.removeClass("hide")
. For checking visibility, I use .hasClass("hide")
.
It's a simple and clear way to check/hide/show elements, if you don't plan to use .toggle()
or .animate()
methods.
$('#clickme').click(function() {
$('#book').toggle('slow', function() {
// Animation complete.
alert($('#book').is(":visible")); //<--- TRUE if Visible False if Hidden
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="clickme">
Click here
</div>
<img id="book" src="https://upload.wikimedia.org/wikipedia/commons/8/87/Google_Chrome_icon_%282011%29.png" alt="" width="300"/>
Source (from my blog):
One can simply use the hidden
or visible
attribute, like:
$('element:hidden')
$('element:visible')
Or you can simplify the same with is as follows.
$(element).is(":visible")
Another answer you should put into consideration is if you are hiding an element, you should use jQuery, but instead of actually hiding it, you remove the whole element, but you copy its HTML content and the tag itself into a jQuery variable, and then all you need to do is test if there is such a tag on the screen, using the normal if (!$('#thetagname').length)
.
When testing an element against :hidden
selector in jQuery it should be considered that an absolute positioned element may be recognized as hidden although their child elements are visible.
This seems somewhat counter-intuitive in the first place – though having a closer look at the jQuery documentation gives the relevant information:
Elements can be considered hidden for several reasons: [...] Their width and height are explicitly set to 0. [...]
So this actually makes sense in regards to the box-model and the computed style for the element. Even if width and height are not set explicitly to 0 they may be set implicitly.
Have a look at the following example:
console.log($('.foo').is(':hidden')); // true
console.log($('.bar').is(':hidden')); // false
.foo {
position: absolute;
left: 10px;
top: 10px;
background: #ff0000;
}
.bar {
position: absolute;
left: 10px;
top: 10px;
width: 20px;
height: 20px;
background: #0000ff;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="foo">
<div class="bar"></div>
</div>
Update for jQuery 3.x:
With jQuery 3 the described behavior will change! Elements will be considered visible if they have any layout boxes, including those of zero width and/or height.
JSFiddle with jQuery 3.0.0-alpha1:
The same JavaScript code will then have this output:
console.log($('.foo').is(':hidden')); // false
console.log($('.bar').is(':hidden')); // false
expect($("#message_div").css("display")).toBe("none");
$(document).ready(function() {
if ($("#checkme:hidden").length) {
console.log('Hidden');
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="checkme" class="product" style="display:none">
<span class="itemlist"><!-- Shows Results for Fish --></span> Category:Fish
<br>Product: Salmon Atlantic
<br>Specie: Salmo salar
<br>Form: Steaks
</div>
To check if it is not visible I use !
:
if ( !$('#book').is(':visible')) {
alert('#book is not visible')
}
Or the following is also the sam, saving the jQuery selector in a variable to have better performance when you need it multiple times:
var $book = $('#book')
if(!$book.is(':visible')) {
alert('#book is not visible')
}
Using classes designated for "hiding" elements is easy and also one of the most efficient methods. Toggling a class 'hidden' with a Display
style of 'none' will perform faster than editing that style directly. I explained some of this pretty thoroughly in Stack Overflow question Turning two elements visible/hidden in the same div.
Here is a truly enlightening video of a Google Tech Talk by Google front-end engineer Nicholas Zakas:
After all, none of examples suits me, so I wrote my own.
Tests (no support of Internet Explorer filter:alpha
):
a) Check if the document is not hidden
b) Check if an element has zero width / height / opacity or display:none
/ visibility:hidden
in inline styles
c) Check if the center (also because it is faster than testing every pixel / corner) of element is not hidden by other element (and all ancestors, example: overflow:hidden
/ scroll / one element over another) or screen edges
d) Check if an element has zero width / height / opacity or display:none
/ visibility:hidden in computed styles (among all ancestors)
Tested on
Android 4.4 (Native browser/Chrome/Firefox), Firefox (Windows/Mac), Chrome (Windows/Mac), Opera (Windows Presto/Mac WebKit), Internet Explorer (Internet Explorer 5-11 document modes + Internet Explorer 8 on a virtual machine), and Safari (Windows/Mac/iOS).
var is_visible = (function () {
var x = window.pageXOffset ? window.pageXOffset + window.innerWidth - 1 : 0,
y = window.pageYOffset ? window.pageYOffset + window.innerHeight - 1 : 0,
relative = !!((!x && !y) || !document.elementFromPoint(x, y));
function inside(child, parent) {
while(child){
if (child === parent) return true;
child = child.parentNode;
}
return false;
};
return function (elem) {
if (
document.hidden ||
elem.offsetWidth==0 ||
elem.offsetHeight==0 ||
elem.style.visibility=='hidden' ||
elem.style.display=='none' ||
elem.style.opacity===0
) return false;
var rect = elem.getBoundingClientRect();
if (relative) {
if (!inside(document.elementFromPoint(rect.left + elem.offsetWidth/2, rect.top + elem.offsetHeight/2),elem)) return false;
} else if (
!inside(document.elementFromPoint(rect.left + elem.offsetWidth/2 + window.pageXOffset, rect.top + elem.offsetHeight/2 + window.pageYOffset), elem) ||
(
rect.top + elem.offsetHeight/2 < 0 ||
rect.left + elem.offsetWidth/2 < 0 ||
rect.bottom - elem.offsetHeight/2 > (window.innerHeight || document.documentElement.clientHeight) ||
rect.right - elem.offsetWidth/2 > (window.innerWidth || document.documentElement.clientWidth)
)
) return false;
if (window.getComputedStyle || elem.currentStyle) {
var el = elem,
comp = null;
while (el) {
if (el === document) {break;} else if(!el.parentNode) return false;
comp = window.getComputedStyle ? window.getComputedStyle(el, null) : el.currentStyle;
if (comp && (comp.visibility=='hidden' || comp.display == 'none' || (typeof comp.opacity !=='undefined' && comp.opacity != 1))) return false;
el = el.parentNode;
}
}
return true;
}
})();
How to use:
is_visible(elem) // boolean
Example of using the visible check for adblocker is activated:
$(document).ready(function(){
if(!$("#ablockercheck").is(":visible"))
$("#ablockermsg").text("Please disable adblocker.").show();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="ad-placement" id="ablockercheck"></div>
<div id="ablockermsg" style="display: none"></div>
"ablockercheck" is a ID which adblocker blocks. So checking it if it is visible you are able to detect if adblocker is turned On.
You need to check both... Display as well as visibility:
if ($(this).css("display") == "none" || $(this).css("visibility") == "hidden") {
// The element is not visible
} else {
// The element is visible
}
If we check for $(this).is(":visible")
, jQuery checks for both the things automatically.
$(document).ready(function() {
var visible = $('#tElement').is(':visible');
if(visible) {
alert("visible");
// Code
}
else
{
alert("hidden");
}
});
<script src="https://code.jquery.com/jquery-1.10.2.js"></script>
<input type="text" id="tElement" style="display:block;">Firstname</input>
Simply check visibility by checking for a boolean value, like:
if (this.hidden === false) {
// Your code
}
I used this code for each function. Otherwise you can use is(':visible')
for checking the visibility of an element.
Because Elements with visibility: hidden or opacity: 0 are considered visible, since they still consume space in the layout
(as described for jQuery :visible Selector) - we can check if element is really visible in this way:
function isElementReallyHidden (el) {
return $(el).is(":hidden") || $(el).css("visibility") == "hidden" || $(el).css('opacity') == 0;
}
var booElementReallyShowed = !isElementReallyHidden(someEl);
$(someEl).parents().each(function () {
if (isElementReallyHidden(this)) {
booElementReallyShowed = false;
}
});
But what if the element's CSS is like the following?
.element{
position: absolute;left:-9999;
}
So this answer to Stack Overflow question How to check if an element is off-screen should also be considered.
A function can be created in order to check for visibility/display attributes in order to gauge whether the element is shown in the UI or not.
function checkUIElementVisible(element) {
return ((element.css('display') !== 'none') && (element.css('visibility') !== 'hidden'));
}
Also here's a ternary conditional expression to check the state of the element and then to toggle it:
$('someElement').on('click', function(){ $('elementToToggle').is(':visible') ? $('elementToToggle').hide('slow') : $('elementToToggle').show('slow'); });
if($('#postcode_div').is(':visible')) {
if($('#postcode_text').val()=='') {
$('#spanPost').text('\u00a0');
} else {
$('#spanPost').text($('#postcode_text').val());
}
.is(":not(':hidden')") /*if shown*/
if($('#id_element').is(":visible")){
alert('shown');
}else{
alert('hidden');
}
I searched for this, and none of the answers are correct for my case, so I've created a function that will return false if one's eyes can't see the element
jQuery.fn.extend({
isvisible: function() {
//
// This function call this: $("div").isvisible()
// Return true if the element is visible
// Return false if the element is not visible for our eyes
//
if ( $(this).css('display') == 'none' ){
console.log("this = " + "display:none");
return false;
}
else if( $(this).css('visibility') == 'hidden' ){
console.log("this = " + "visibility:hidden");
return false;
}
else if( $(this).css('opacity') == '0' ){
console.log("this = " + "opacity:0");
return false;
}
else{
console.log("this = " + "Is Visible");
return true;
}
}
});
As hide()
, show()
and toggle()
attaches inline css (display:none or display:block) to element.
Similarly, we can easily use the ternary operator to check whether the element is hidden or visible by checking display CSS.
UPDATE:
So we can check for the property of an element that makes it invisible. So they are display: none
and visibility: "hidden";
We can create an object for checking property responsible for hiding element:
var hiddenCssProps = {
display: "none",
visibility: "hidden"
}
We can check by looping through each key value in object matching if element property for key matches with hidden property value.
var isHidden = false;
for(key in hiddenCssProps) {
if($('#element').css(key) == hiddenCssProps[key]) {
isHidden = true;
}
}
If you want to check property like element height: 0 or width: 0 or more, you can extend this object and add more property to it and can check.
There are quite a few ways to check if an element is visible or hidden in jQuery.
Demo HTML for example reference
<div id="content">Content</div>
<div id="content2" style="display:none">Content2</div>
Use Visibility Filter Selector $('element:hidden')
or $('element:visible')
$('element:hidden')
: Selects all elements that are hidden.
Example:
$('#content2:hidden').show();
$('element:visible')
: Selects all elements that are visible.
Example:
$('#content:visible').css('color', '#EEE');
Read more at http://api.jquery.com/category/selectors/visibility-filter-selectors/
Use is()
Filtering
Example:
$('#content').is(":visible").css('color', '#EEE');
Or checking condition
if ($('#content').is(":visible")) {
// Perform action
}
Read more at http://api.jquery.com/is/
Just simply check if that element is visible and it will return a boolean. jQuery hides the elements by adding display none to the element, so if you want to use pure JavaScript, you can still do that, for example:
if (document.getElementById("element").style.display === 'block') {
// Your element is visible; do whatever you'd like
}
Also, you can use jQuery as it seems the rest of your code is using that and you have smaller block of code. Something like the below in jQuery does the same trick for you:
if ($(element).is(":visible")) {
// Your element is visible, do whatever you'd like
};
Also using the css
method in jQuery can result in the same thing:
if ($(element).css('display') === 'block') {
// Your element is visible, do whatever you'd like
}
Also in case of checking for visibility and display, you can do the below:
if ($(this).css("display") === "block" || $(this).css("visibility") === "visible") {
// Your element is visible, do whatever you'd like
}
This is how jQuery internally solves this problem:
jQuery.expr.pseudos.visible = function( elem ) {
return !!( elem.offsetWidth || elem.offsetHeight || elem.getClientRects().length );
};
If you don't use jQuery, you can just leverage this code and turn it into your own function:
function isVisible(elem) {
return !!( elem.offsetWidth || elem.offsetHeight || elem.getClientRects().length );
};
Which isVisible
will return true
as long as the element is visible.
You can use this:
$(element).is(':visible');
$(document).ready(function()
{
$("#toggle").click(function()
{
$("#content").toggle();
});
$("#visiblity").click(function()
{
if( $('#content').is(':visible') )
{
alert("visible"); // Put your code for visibility
}
else
{
alert("hidden");
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.2/jquery.min.js"></script>
<p id="content">This is a Content</p>
<button id="toggle">Toggle Content Visibility</button>
<button id="visibility">Check Visibility</button>
I just want to clarify that, in jQuery,
Elements can be considered hidden for several reasons:
- They have a CSS display value of none.
- They are form elements with type="hidden".
- Their width and height are explicitly set to 0.
- An ancestor element is hidden, so the element is not shown on the page.
Elements with visibility: hidden or opacity: 0 are considered to be visible, since they still consume space in the layout. During animations that hide an element, the element is considered to be visible until the end of the animation.
if($('.element').is(':hidden')) {
// Do something
}
This is some option to check that tag is visible or not
// using a pure CSS selector
if ($('p:visible')) {
alert('Paragraphs are visible (checked using a CSS selector) !');
};
// using jQuery's is() method
if ($('p').is(':visible')) {
alert('Paragraphs are visible (checked using is() method)!');
};
// using jQuery's filter() method
if ($('p').filter(':visible')) {
alert('Paragraphs are visible (checked using filter() method)!');
};
// you can use :hidden instead of :visible to reverse the logic and check if an element is hidden
// if ($('p:hidden')) {
// do something
// };
You can just add a class when it is visible. Add a class, show
. Then check for it have a class:
$('#elementId').hasClass('show');
It returns true if you have the show
class.
Add CSS like this:
.show{ display: block; }
$( "div:visible" ).click(function() {
$( this ).css( "background", "yellow" );
});
$( "button" ).click(function() {
$( "div:hidden" ).show( "fast" );
});
API Documentation: visible Selector
<script>
if ($("#myelement").is(":visible")){alert ("#myelement is visible");}
if ($("#myelement").is(":hidden")){alert ("#myelement is hidden"); }
</script>
$("#myelement div:visible").each( function() {
//Do something
});
This is how jQuery implements this feature:
jQuery.expr.filters.visible = function( elem ) {
return !!( elem.offsetWidth || elem.offsetHeight || elem.getClientRects().length );
};
Using Element.getBoundingClientRect() you can easily detect whether or not your element is within the boundaries of your viewport (i.e. onscreen or offscreen):
jQuery.expr.filters.offscreen = function(el) {
var rect = el.getBoundingClientRect();
return (
(rect.x + rect.width) < 0
|| (rect.y + rect.height) < 0
|| (rect.x > window.innerWidth || rect.y > window.innerHeight)
);
};
You could then use that in several ways:
// Returns all elements that are offscreen
$(':offscreen');
// Boolean returned if element is offscreen
$('div').is(':offscreen');
If you use Angular, check: Don’t use hidden attribute with Angular
There are too many methods to check for hidden elements. This is the best choice (I just recommended you):
Using jQuery, make an element, "display:none", in CSS for hidden.
The point is:
$('element:visible')
And an example for use:
$('element:visible').show();
Simply check for the display
attribute (or visibility
depending on what kind of invisibility you prefer). Example:
if ($('#invisible').css('display') == 'none') {
// This means the HTML element with ID 'invisible' has its 'display' attribute set to 'none'
}
Using hidden selection you can match all hidden elements
$('element:hidden')
Using Visible selection you can match all visible elements
$('element:visible')
If you want to check if an element is visible on the page, depending on the visibility of its parent, you can check if width
and height
of the element are both equal to 0
.
jQuery
$element.width() === 0 && $element.height() === 0
Vanilla
element.clientWidth === 0 && element.clientHeight === 0
Or
element.offsetWidth === 0 && element.offsetHeight === 0
A jQuery solution, but it is still a bit better for those who want to change the button text as well:
$(function(){
$("#showHide").click(function(){
var btn = $(this);
$("#content").toggle(function () {
btn.text($(this).css("display") === 'none' ? "Show" : "Hide");
});
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button id="showHide">Hide</button>
<div id="content">
<h2>Some content</h2>
<p>
What is Lorem Ipsum? Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a type specimen book. It has survived not only five centuries, but also the leap into electronic typesetting, remaining essentially unchanged.
</p>
</div>
It returns false
if the element is not visible.
function checkVisible(e) {
if (!(e instanceof Element)) throw Error('not an Element');
const elementStyle = getComputedStyle(e);
if (elementStyle.display === 'none' || elementStyle.visibility !== 'visible' || elementStyle.opacity < 0.1) return false;
if (e.offsetWidth + e.offsetHeight + e.getBoundingClientRect().height +
e.getBoundingClientRect().width === 0) {
return false;
}
const elemCenter = {
x: e.getBoundingClientRect().left + e.offsetWidth / 2,
y: e.getBoundingClientRect().top + e.offsetHeight / 2
};
if (elemCenter.x < 0 || elemCenter.y < 0) return false;
if (elemCenter.x > (document.documentElement.clientWidth || window.innerWidth)) return false;
if (elemCenter.y > (document.documentElement.clientHeight || window.innerHeight)) return false;
let pointContainer = document.elementFromPoint(elemCenter.x, elemCenter.y);
do {
if (pointContainer === e) return true;
} while (pointContainer = pointContainer.parentNode);
return false;
}
To be fair the question pre-dates this answer.
I add it not to criticise the OP, but to help anyone still asking this question.
The correct way to determine whether something is visible is to consult your view-model;
If you don't know what that means then you are about to embark on a journey of discovery that will make your work a great deal less difficult.
Here's an overview of the model-view-view-model architecture (MVVM).
KnockoutJS is a binding library that will let you try this stuff out without learning an entire framework.
And here's some JavaScript code and a DIV that may or may not be visible.
<html>
<body>
<script src="https://cdnjs.cloudflare.com/ajax/libs/knockout/3.4.1/knockout-min.js"></script>
<script>
var vm = {
IsDivVisible: ko.observable(true);
}
vm.toggle = function(data, event) {
// Get current visibility state for the div
var x = IsDivVisible();
// Set it to the opposite
IsDivVisible(!x);
}
ko.applyBinding(vm);
</script>
<div data-bind="visible: IsDivVisible">Peekaboo!</div>
<button data-bind="click: toggle">Toggle the div's visibility</button>
</body>
</html>
Notice that the toggle function does not consult the DOM to determine the visibility of the div; it consults the view-model.
You can use a CSS class when it visible or hidden by toggling the class:
.show{ display :block; }
Set your jQuery toggleClass()
or addClass()
or removeClass();
.
As an example,
jQuery('#myID').toggleClass('show')
The above code will add show
css class when the element don't have show
and will remove when it has show
class.
And when you are checking if it visible or not, You can follow this jQuery code,
jQuery('#myID').hasClass('show');
Above code will return a boolean (true) when #myID
element has our class (show
) and false when it don't have the (show
) class.
isHidden = function(element){
return (element.style.display === "none");
};
if(isHidden($("element")) == true){
// Something
}
You can use jQuery's is()
function to check the selected element visible or hidden. This method traverses along the DOM elements to find a match, which satisfies the passed parameter. It will return true if there is a match otherwise returns false.
<script>
($("#myelement").is(":visible"))? alert("#myelement is visible") : alert("#myelement is hidden");
</script>
content.style.display != 'none'
function toggle() {
$(content).toggle();
let visible= content.style.display != 'none'
console.log('visible:', visible);
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<button onclick="toggle()">Show/hide</button>
<div id="content">ABC</div>
Instead of writing an event
for every single element
, do this:
$('div').each(function(){
if($(this).css('display') === 'none'){
$(this).css({'display':'block'});
}
});
Also you can use it on the inputs:
$('input').each(function(){
if($(this).attr('type') === 'hidden'){
$(this).attr('type', 'text');
}
});
The below code checks if an element is hidden in jQuery or visible
// You can also do this...
$("button").click(function(){
// show hide paragraph on button click
$("p").toggle("slow", function(){
// check paragraph once toggle effect is completed
if($("p").is(":visible")){
alert("The paragraph is visible.");
} else{
alert("The paragraph is hidden.");
}
});
});
hideShow(){
$("#accordionZiarat").hide();
// Checks CSS content for display:[none|block], ignores visibility:[true|false]
if ($("#accordionZiarat").is(":visible")) {
$("#accordionZiarat").hide();
}
else if ($("#accordionZiarat").is(":hidden")) {
$("#accordionZiarat").show();
}
else{
}
There is two way to check visibility of element.
if($('.selector').is(':visible')){
// element is visible
}else{
// element is visible
}
or
if($('.selector:visible')){
// element is visible
}else{
// element is visible
}
The easiest answer to this question is this:
function checkUIElementVisible(element) {
return ((element.css('display') !== 'none') && (element.css('visibility') !== 'hidden'));
}
$('someElement').on('click', function(){ $('elementToToggle').is(':visible')
if($(element).is(":visible")) {
console.log('element is visible');
} else {
console.log('element is not visible');
}
if you hide with class - d-none
if (!$('#ele').hasClass('d-none')) {
$('#ele').addClass('d-none'); //hide
}